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x^2+16151x-16151=0
a = 1; b = 16151; c = -16151;
Δ = b2-4ac
Δ = 161512-4·1·(-16151)
Δ = 260919405
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{260919405}=\sqrt{9*28991045}=\sqrt{9}*\sqrt{28991045}=3\sqrt{28991045}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16151)-3\sqrt{28991045}}{2*1}=\frac{-16151-3\sqrt{28991045}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16151)+3\sqrt{28991045}}{2*1}=\frac{-16151+3\sqrt{28991045}}{2} $
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